![]() ![]() It suffices, for example, that each protein contains, in a different order, the same two recognized domains, but these domains do not have to cover the entire sequences. How many four- digit number can be formed from the numbers 1,3,4,6,8,and 9if repetition of digits is not allowed? n= (6)(5)(4)(3). For example, the proteins do not have to be of similar sizes for a circular permutation to be considered. if there are 3 roads from town A to town B and 4 roads from town B to town C, In how many ways can one go from Town A to town C and Back to Town A, through Town B, without passing through the same road twice? A to B= 3, B to C= 4, C to B=3, B to A=2 n= (3)(4)(3)(2) n= 72 possible outcomes 9.If Jun has 12 T-Shirt, 6 pairs of pants, and 3 pairs of shoes, how many possibilities can he dress himself up for the day? n= (12)(6)(3) n= 216 possible outfits 10. This is related to the rearrangement of the elements of S in which each element s is replaced by the corresponding f(s). In how many ways can a president, a vice president, a secretary, and a treasurer be selected from the board? n= (12)(11)(10)(9) n= 11,880 possible ways of electing president, vice president, secretary and treasurer 8. If all of the balls were the same color there would only be one distinguishable permutation in lining them up in a row because the balls themselves would look the same no. Solved Examples Using Permutation and Combination Formulas. If there is a collection of 15 balls of various colors, then the number of permutations in lining the balls up in a row is 15P15 15. ![]() suppose that in a certain association, there are 12 elected members of the board of Directors. Permutation and combination form the principles of counting and they are applied in various. ![]() if the display window has 5 mannequins, in how many ways can she dress them up? n= (8)(7)(6)(5)(4) n= 6720 7. The permutation and combination question we have done so far are basically about selecting objects. A dress- shop owner has 8 new dresses that she wants to display in the window. In how many ways can you place 9 different books on a shelf if there is space enough for only 5 books. How many choices do you have for your meal if there are 3 choices of meat dishes and 2 choice of vegetable dishes n= 3 r= 2 3! all over (3-2)! =6 5. (We can also arrange just part of the set of objects.) In a permutation, the order that we arrange the objects in is important. We will evaluate permutation of n objects taken r at a time. You want to order your lunch from the school canteen, which offers student meals consisting of 1 cup of rice, 1 meat dish, and 1 vegetable dish. In this video, we will illustrate permutation (linear permutation). In how many ways can Along Rosa arrange 6 potted plants in a row just simply get the factorial of 6 6! = 720 3.In How many ways can 5 people arrange themselves in a row for picture taking? just simply get the factorial of 5 5! = 120 4. In how many possible ways can they be arranged as First,sencond, and third N=10 R=3 10! all over (10-3)! =720 2. ![]()
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